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传说中隐藏着绝世武学的“翡翠娃娃”重现江湖，掀起一场争夺战。长风镖局的少主郭旭，为了借“翡翠娃娃”上记栽的医学宝典，替两代世交云家庄的云五少爷治疗宿疾，宁冒天下之大不讳，在霹雳飞刀封平，快剑辛力及程铁衣，程采玉兄妹协助下，护送“翡翠娃娃”前往云家庄。 　　保镖途中，有官府的锦衣卫指挥使翁泰北，名门正派少林、华山、青城以及邪恶的天下第一帮天幽帮、四川唐门、七星堡等等各路黑白人物明抢暗夺，又有性烈如火、情痴若狂的血手胭脂的纠缠。多情多义的风流少侠郭旭，如何将这趟镖送到目的地呢？Focus 1. Level 2 is calculated only on the basis of Level 1此剧是以女性角色为中心的悬疑心理惊悚剧,主要讲述了遮掩阴暗面,通过某人的牺牲来维持的社会为背景,刻画了拥有多样欲望和心理的人物们以及他们之间错综复杂关系的电视剧。五个年轻的徒步旅行者在红木森林中鬼鬼祟祟的出现的阴影下，发现了一个早在淘金热时期就被遗弃的金矿，并在追求容易获得的财富时陷入疯狂和贪婪。In addition to solving the port problem of A, the serial number problem also needs to be paid attention to. The serial number corresponds to the sliding window. The fake TCP packet needs to be filled with the serial number. If the value of the serial number is not in the sliding window of B when it is sent to B before A, B will actively discard it. So we need to find the serial number that can fall into the sliding window between AB at that time. This can be solved violently, because the length of a sequence is 32 bits, and the value range is 0-4294967296. If the window size is like 65535 under Windows I caught in the above figure, I only need to divide, and I know that at most I only need to send 65537 (4294967296/65535=65537) packets to have a sequence number fall into the sliding window. The desired value can be calculated quickly by exhaustion on multiple control hosts.OvR has the advantages of fewer classifiers, less storage overhead and less test time than OvO. The disadvantage is that when there are many categories, the training time is long.