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许愿（夏雨饰），北京潘家园小古董店\"四悔斋〃的老板，古董鉴宝界最具权威的\"五脉梅花\"家族之一许家，唯一的传人。为了楸出隐藏在五脉之中的〃老朝奉〃造假势力，许愿孤身一人入局破局，与 庞大的古董造假集团展开层层较量，却被设局指引牵扯出两幅《清明上河图》真赝难辨的惊天秘密。随着迷局的层层解开，境外神秘的造假势力也浮出水面，而这些竟然都与当年许愿爷爷的护宝冤案有着千丝万缕的关系。为了查出前世真相，许愿再度联手投靠于\"老朝奉\"的药不然（魏晨饰），但不曾想这所有的一切都尽在老朝奉的掌握之中，而老朝奉势力的背后还藏着更大的谜团。昔日人气歌手向东南（陈学冬 饰）一朝落魄，潦倒之际接到真人秀邀约重返高中担任音乐老师，遇上严谨认真武力值爆表的英语老师苏淇（张佳宁 饰），班主任之争一触即发，三观不合的他们如何求同存异？神秘教导主任（张俪 饰）的出现又会给他们的校园生活带来哪些挑战？作为向东南最强助理（王瑞昌 饰）的林声，是否能让向东南的事业触底反弹？高一八班教师天团与尹星尧（边程 饰）为代表的学生大队之间的推拉过招即将上演！Breaking the "Miracle of Genius High Jumpers"//265其实这很多事情确实是他一厢情愿的想法，不过吕雉头脑聪明，对局势和利害关系了解的比较透彻，所以说出来的话比较有说服力。In addition to solving the port problem of A, the serial number problem also needs to be paid attention to. The serial number corresponds to the sliding window. The fake TCP packet needs to be filled with the serial number. If the value of the serial number is not in the sliding window of B when it is sent to B before A, B will actively discard it. So we need to find the serial number that can fall into the sliding window between AB at that time. This can be solved violently, because the length of a sequence is 32 bits, and the value range is 0-4294967296. If the window size is like 65535 under Windows I caught in the above figure, I only need to divide, and I know that at most I only need to send 65537 (4294967296/65535=65537) packets to have a sequence number fall into the sliding window. The desired value can be calculated quickly by exhaustion on multiple control hosts.//and B methods; Method A and method B write specific business logic in subclasses in turn.那个第四更估计没有了，明天继续三更。